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Gcc Error Non-template Used As Template

What's the syntax / semantics for a "function template"? Comment 4 Andrew Pinski 2006-10-14 18:15:38 UTC I think this is more complicated than just DR 224. Unproven vs. I'm wondering whether this change was intentional and whether there's a good reason for this change (in a stable branch). $ g++-4.1 -c pair.c x.c:32: error: non-template 'pair' used as template have a peek at these guys

asked 4 years ago viewed 1196 times active 4 years ago Related 1errors porting C++ templates from GCC to Visual C++54C++11 make_pair with specified template parameters doesn't compile5How should I use small amount of code used only when T is int ... } template<> inline void foo_part(const std::string& x) { // ... Well, I learn something every day because if the return type is int rather than void, the code must be int friend ::operator+<>(int foo) and I never knew the 'friend' went See PR 9634. http://stackoverflow.com/questions/21378150/how-to-fix-compile-error-non-template-iterator1-used-as-template

The transformation T on the set of all continuous functions that is defined by T(f) = f (1) is a linear transformation. small amount of code used only when T is std::string ... It all gets figured out automatically. struct A { template operator T*(); // conversion to pointer to any type }; // out-of-class definition template A::operator T*() {return nullptr;} // explicit specialization for char*

Comment 3 ron 2004-08-20 16:35:04 UTC (In reply to comment #2) > Note that this works though: > friend void ::operator+<>(int, foo); > > I think this is correct as Comeau Must be a regression. Compute the kangaroo sequence more hot questions question feed lang-cpp about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / But if you don't trust me or are simply curious, the rationale is given earlier.

If that's confusing, click your heels twice, think of Kansas, and repeat after me, "I will do it anyway even though it's confusing." You can trust me on this one. more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed How do I explicitly select which version of a function template should get called? http://stackoverflow.com/questions/12959250/why-am-i-getting-the-error-non-template-f-used-as-template Relation between representations of p-adic groups and affine Hecke algebras How does NumPy solve least squares for underdetermined systems?

Is there a Korean word for 'Syllable Block'? However the details for implementing that observable behavior is slightly different for bool and floating point types, so template specialization is a good approach. In order for the compiler to generate the code, it must see both the template definition (not just declaration) and the specific types/whatever used to "fill in" the template. Export The $PATH Variable, Line-By-Line Chebyshev Rotation Developing web applications for long lifespan (20+ years) Convert mp4 to mp3 Using Shell Script Generate a 6 character string from a 15 character

Browse other questions tagged c++ templates struct or ask your own question. c++ templates struct share|improve this question edited Oct 18 '12 at 16:31 Coding Mash 3,20451642 asked Oct 18 '12 at 16:23 template boy 4,0301956 add a comment| 1 Answer 1 active The code compiles fine within VS2012, but fails in VS2013 and gcc 4.2.x: #include namespace utf { class klar{ //my test class public: template class iterator1 { De kio “saluton” estas la rekta objekto?

The other solution is to leave the definition of the template function in the .cpp file and simply add the line template void foo(); to that file: // File "foo.cpp" #include up vote 15 down vote favorite 3 This snippet (taken from this question) compiles fine with g++ (as seen), so long the template before the return type is there. There are two solutions for this. For example, suppose your template function has a bunch of common code along with a relatively small amount of T-specific code (conceptual only; not C++): template void foo(const T& x)

What kind of distribution is this? Suppose you have a template Foo defined like this: template class Foo { public: Foo(); void someMethod(T x); private: T x; }; Along with similar definitions for the member functions: Without this space, the C++98/C++03 compiler would see a >> (right-shift) token instead of two >'s. I think my use of typename in the function body is correct, however, I keep getting the following error: source.cpp: In function 'void f()': source.cpp:11:19: error: non-template 'f' used as template

Don't they? Developing web applications for long lifespan (20+ years) Where are sudo's insults stored? it is impossible to define something that is not declared –user396672 Apr 9 '12 at 14:02 Oh, of course.

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Book of zen kōans What are oxidation states used for? Sometimes, you do want to be explicit about the types used. Unproven vs. Most of the time it can do that successfully, but every once in a while you may want to help the compiler deduce the right type -- either because it cannot

Function templates participate in name resolution for overloaded functions, but the rules are different. A template is a cookie-cutter that specifies how to cut cookies that all look pretty much the same (although the cookies can be made of various kinds of dough, they'll all Which compiler is right here? As an example, consider the header file foo.h which contains the following template function declaration: // File "foo.h" template extern void foo(); Now suppose file foo.cpp actually defines that template

thanks a lot! –muffmolch Jan 27 '14 at 10:22 add a comment| Not the answer you're looking for? There are two solutions for this. Finding good names for constraints can be hard. At the time of this writing, it works with the following compilers: Comeau C++, Intel C++, CodeWarrior C++, gcc, Borland C++, Microsoft Visual C++, and EDG C++.

template struct A { void f(int); // non-template member template void f(T2); // member template }; //template member definition template template void A::f(T2) { // Terms of Use Privacy Policy cppreference.com Search Create account Log in Namespaces Page Discussion Variants Views View Edit History Actions Member templates From cppreference.com < cpp‎ | language C++ Language Instead, you add the template before the class definition (the T can be any identifier you want, T is just the most commonly used one, especially in examples). Your compiler probably doesn't remember the details of one .cpp file while it is compiling another .cpp file.

It is possible, however, to "cheat" your way out of specifying all those arguments and use the defaults.